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Answer:
[tex]x=\sqrt{23}[/tex]
Step-by-step explanation:
So the eqaution for the hypotonuse is [tex]a^{2}+b^{2} =c^{2}[/tex]
Therefore...
[tex]\sqrt{16} +\sqrt{x^{2} }=\sqrt{27}\\ 4+x =\sqrt{27} \\x=\sqrt{23}[/tex]