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The equation 2x + 3y = 1,470 represents Sal's profits last month, where x is the number of sandwich lunch specials sold and y is the number of wrap lunch specials sold.

1. Change the equation to slope-intercept form. Identify the slope and y-intercept of the equation. Be sure to show all your work.
2. Describe how you would graph this line using the slope-intercept method. Be sure to write using complete sentences.
3. Write the equation in function notation. Explain what the graph of the function represents. Be sure to use complete sentences.
4. Graph the function. On the graph, make sure to label the intercepts. You may graph your equation by hand on a piece of paper and scan your work or you may use graphing technology.
5. Suppose Sal's total profit on lunch specials for the next month is $1,593. The profit amounts are the same: $2 for each sandwich and $3 for each wrap. In a paragraph of at least three complete sentences, explain how the graphs of the functions for the two months are similar and how they are different.

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Answer:

1.) the y intercept is 490 and the slope is -2/3x2.) First, I would find the point (0,490) and plot a point there. Then I would use our slope -2/3 to figure out what direction and what angle the line goes by counting 2 down and 3 to the right3.) f(x)= -2/3x+490The graph represents how many wraps could've been sold for each number of sandwich sales to keep the same profit of $1,470.  4.) graph down below5.) the profits are the same (slope) but the y intercept is higher then the original graph.6.) y=-2/3x+300

Step-by-step explanation:

some of these are part of the problem as well.1.)  2x+3y=1,470  3y=-2x+1,470-2x+1,470/3-2/3x + 490y=-2/3x + 490the y intercept is 490 and the slope is -2/3x2.) First, I would find the point (0,490) and plot a point there. Then I would use our slope -2/3 to figure out what direction and what angle the line goes by counting 2 down and 3 to the right3.) f(x)= -2/3x+490The graph represents how many wraps could've been sold for each number of sandwich sales to keep the same profit of $1,470.  5.) 2x+3y=1,5933y=-2x+1,593y=-2/3x+531the profits are the same (slope) but the y intercept is higher then the original graph.6.) (150, 200) (300, 100)y intercept= 300m= 100-200/300-150 = -100/150 = -2/3y=-2/3x+300

Answer:

1.) the y intercept is 490 and the slope is -2/3x2.) First, I would find the point (0,490) and plot a point there. Then I would use our slope -2/3 to figure out what direction and what angle the line goes by counting 2 down and 3 to the right3.) f(x)= -2/3x+490The graph represents how many wraps could've been sold for each number of sandwich sales to keep the same profit of $1,470.  4.) graph down below5.) the profits are the same (slope) but the y intercept is higher then the original graph.6.) y=-2/3x+300

Step-by-step explanation:

some of these are part of the problem as well.1.)  2x+3y=1,470  3y=-2x+1,470-2x+1,470/3-2/3x + 490y=-2/3x + 490the y intercept is 490 and the slope is -2/3x2.) First, I would find the point (0,490) and plot a point there. Then I would use our slope -2/3 to figure out what direction and what angle the line goes by counting 2 down and 3 to the right3.) f(x)= -2/3x+490The graph represents how many wraps could've been sold for each number of sandwich sales to keep the same profit of $1,470.  5.) 2x+3y=1,5933y=-2x+1,593y=-2/3x+531the profits are the same (slope) but the y intercept is higher then the original graph.6.) (150, 200) (300, 100)y intercept= 300m= 100-200/300-150 = -100/150 = -2/3y=-2/3x+300

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