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what is the missing number if the mean of 48,33 is 41

Sagot :

SpiritInlyidn

Answer:

42

Step-by-step explanation:

let's make the missing number x

[tex]mean = \frac{sum \: of \: numbers}{how \: many \: numbers \: there \: are} [/tex]

[tex]41 = \frac{48 + 33 + x}{3} [/tex]

multiply 3 on both sides to get rid of the fraction, 41 × 3 = 123

[tex]123 = 48 + 33 + x[/tex]

simplify the right side, 48 + 33 = 81

[tex]123 = 81 + x[/tex]

subtract 81 on both sides

[tex]123 - 81 = x[/tex]

[tex]x = 42[/tex]

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