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a room has floor dimensions of 4 meters by 6 meters the height of the basement is 7 meters what is the total area of the walls

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The total area of the walls is 140 m²

Since the room is in the shape of a cuboid, and we require the area of the walls of the room, the walls of the cuboid are the walls of the room.

Area of the room

So, the total surface area of a cuboid is A = 2(lb + lh + bh) where

  • l = length of room,
  • b = breadth of room and
  • h = height of room.

Since we require the total area of the walls, lb which is the area of the floor is removed from the equation.

Area of the walls

So, the area of the walls is A' = 2(lh + bh)

= 2h(l + b)

Since the dimensions of the floor are 4 meters by 6 meters and the height of the basement is 7 m. So,

  • l = 4 m,
  • b = 6 m and
  • h = 7 m

So, substituting the values of the variables into the equation, we have

A' = 2h(l + b)

A' = 2 × 7 m × (4 m + 6 m)

A' = 14 m × 10 m

A' = 140 m²

So, the total area of the walls is 140 m²

Learn more about total surface area of room here:

https://brainly.com/question/17048283

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