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In her calculations, Rosita will be using the square root of 2 often. She wants to use as few digits as possible, but at the same time have sufficient precision. How should Rosita round the square root of 2 so that the approximation times 5 is greater than 7.05?

Sagot :

Testing the multiplication for each case, it is found that she should round the square root of 2 to three decimal digits.

What is the square root of 2?

The square root of 2 is given by:

[tex]\sqrt{2} = 1.41421356237[/tex]

With one decimal digit, the result of the multiplication is:

[tex]5 \times \sqrt{2} = 5 \times 1.4 = 7 < 7.05[/tex]

With two decimal digits, the result of the multiplication is:

[tex]5 \times \sqrt{2} = 5 \times 1.41 = 7.05 = 7.05[/tex]

With three decimal digits, the result of the multiplication is:

[tex]5 \times \sqrt{2} = 5 \times 1.414 = 7.07 > 7.05[/tex]

Hence, she should round the square root of 2 to three decimal digits.

You can learn more about rounding at https://brainly.com/question/17248958

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