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Sagot :
The given exponential function can be used to determine the
population of the fish at different times.
Response:
1. 200
2. 0.05
3. Please find attached the graph of the exponential function and the table
[tex]\begin{array}{|c|c|c}x&f(x)\\0&200 & y-intercept\\1&210\\3&231.525\\4&243.1\\5&255.26\end{array}[/tex]
4. Range; [0, ∞)
Domain: [200, ∞)
5. 346 fishes (approximate value)
How is the population of the fish obtained from the exponential function?
The given function is f(x) = 200·(1.05)ˣ
1. The initial population is given by the value of the function when x = 0,
which is given as follows;
At x = 0, f(0) = 200·(1.05)⁰ = 200
- The initial population of the fish is 200
2. The rate of growth of the fish from the exponential function is given as follows;
The growth factor = 1.05
- The growth rate = 0.05
3. Please find attached the graph of the exponential function created
with MS Excel.
The asymptote of the exponential function is the line, y = 0
The table of values is presented as follows;
[tex]\begin{array}{|c|c|c}x&f(x)\\0&200 & y-intercept\\1&210\\3&231.525\\4&243.1\\5&255.26\end{array}[/tex]
4. The domain is the possible x-values which is; 0 ≤ x < ∞
The range is the possible y-values which is; 200 ≤ f(x) < ∞
Which gives;
- Domain; [0, ∞)
- Range: [200, ∞)
5. The population of the fish after 11 years is f(11) = 200·(1.05)¹¹
f(11) = 200 × (1.05)¹¹ ≈ 342
- The population of the fish after 11 years is 346 (fishes)
Learn more about exponential function here:
https://brainly.com/question/15662160
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