Kaliaratliffidn
Answered

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Please HELP!!

Solve the system of linear equations by substitution

2x+3y=0
8x +9y =18

Sagot :

AutumnBellsidn

Answer:

Step-by-step explanation:

Step 1:

Isolate x (1st Equation)

2x + 3y = 0

     - 3y = -3y

       2x = -3y

Step 2:

Divide both sides by 2

x = -3y/2

Step 3:

Replace the x from 8x with -3y/2 and Solve the equation

8(-3y/2) + 9y = 18

-12y + 9y = 18

-3y = 18

y = -6

Step 4:

Go back to the 1st equation and replace the y from 3y with -6. You are now solving for x. Solve the equation.
2x + 3(-6) = 0

2x - 18 = 0

    + 18 = +18

      2x = 18

x = 9

Step 5:

Write your final answer.

(x, y) = (9, -6)

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