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Answer:
[tex]x=\frac{2\pm i\sqrt{6}}{2}[/tex]
Step-by-step explanation:
[tex]-2x^2+4x=5\\\\-2x^2+4x-5=0\\\\x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\ \\x=\frac{-4\pm\sqrt{(4)^2-4(-2)(-5)}}{2(-2)}\\\\x=\frac{-4\pm\sqrt{16-40}}{-4}\\\\x=\frac{-4\pm\sqrt{-24}}{-4}\\ \\x=\frac{-4\pm2i\sqrt{6}}{-4}\\ \\x=\frac{2\pm i\sqrt{6}}{2}[/tex]