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Write a sine function that has a midline of 5, an amplitude of 4 and a period of 7/5

Sagot :

Answer:

[tex]y=4sin(\frac{10\pi}{7}x)+5[/tex]

Step-by-step explanation:

Recall formula

[tex]y=asin(bx+c)+d\\\\y=4sin(bx)+5[/tex]

Determine b from period

[tex]\frac{2\pi}{b}=\frac{7}{5}\\ \\ 10\pi=7b\\\\b=\frac{10\pi}{7}[/tex]

Final Equation

[tex]y=4sin(\frac{10\pi}{7}x)+5[/tex]

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