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A source charge of 5. 0 µC generates an electric field of 3. 93 × 105 at the location of a test charge. How far is the test charge from the source charge?.

Sagot :

Genius365idn

Answer:

r = 0.338 meters

Explanation:

Q = Source charge

q = Test charge

5μC= 5*10^-6 C

Start with the electric field equation:

[tex]E = \frac{F}{q}[/tex]

and Coulombs law

[tex]F=\frac{k|Qq|}{r^2}[/tex]

Combining these functions we get:

[tex]E=\frac{k|Q|}{r^2}[/tex]

As you can see the test charge cancels so we do not need the value of it.

Plug in your numbers:

[tex]3.93*10^5=\frac{(8.99*10^9)(5*10^-^6)}{r^2}[/tex]

solve for r

[tex]r=\sqrt{\frac{(8.99*10^9)(5*10^-^6)}{(3.93*10^5)} }[/tex]

[tex]r= 0.338 meters[/tex]

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