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How many atoms of Ca are present in 80.156 grams of Ca?

1.2044 × 10^24
2.4088 × 10^24
4.8270 × 10^25
1.9346 × 10^27

Sagot :

Eduard22slyidn

The number of atoms present in 80.156 grams of Ca is 1.204×10²⁴ atoms

Avogadro's hypothesis

From Avogadro's hypothesis,

1 mole of Ca = 6.02×10²³ atoms

But

1 mole of Ca = 40.078 g

Thus,

40.078 g of Ca = 6.02×10²³ atoms

How to determine the atoms in 80.156 g of Ca

40.078 g of Ca = 6.02×10²³ atoms

Therefore,

80.156 g of Ca = (80.156 × 6.02×10²³) / 40.078

80.156 g of Ca = 1.204×10²⁴ atoms

Thus, 1.204×10²⁴ atoms is present in 80.156 g of Ca.

Learn more about Avogadro's number:

https://brainly.com/question/26141731

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