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Hi there!
Recall the equation for work given a potential difference and charge:
[tex]\large\boxed{W = qV}[/tex]
W = Work (J)
q = charge (C)
V = Potential difference (V)
The work is equivalent to the change in KINETIC ENERGY, and only depends on the particle's charge and the potential difference that it experiences. Mass has no impact on this.
Thus:
[tex]W' = (2Q)(V) = 2W[/tex]
This is equivalent to:
[tex]\large\boxed{2W = \text{ d) } 2K}}[/tex]