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The spring in a dart gun has a force constant k of 200 N/m. If the spring is compressed 0.02 m prior to shooting the dart, how much kinetic energy will the spring impart to a dart

Sagot :

Leenaidn

Hi there!

Recall the equation for Spring Potential Energy:
[tex]\large\boxed{PE = \frac{1}{2}kx^2}[/tex]

PE = Potential Energy (J)
k = Spring Constant (N/m)
x = displacement from equilibrium (m)

Plug in the givens:

[tex]PE = \frac{1}{2}(200)(0.02^2) = 0.04 J[/tex]


All of the potential energy will be converted to kinetic energy when the spring is released, so:
[tex]\large\boxed{KE = 0.04 J}[/tex]

Robecornibeidn

Answer:

0.04 J

Explanation:

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