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Find the midpoint of the line segment with end coordinates of: (-4,-2) and (-2, -10)​

Find The Midpoint Of The Line Segment With End Coordinates Of 42 And 2 10 class=

Sagot :

Answer:

(-3,-6)

Step-by-step explanation:

midpoint formula : [tex](\frac{x_1+x_2}{2} ,\frac{y_1+y_2}{2} )[/tex]

where the x and y values derive from the given points

The points given are (-4,-2) and (-2,-10)

The first step is to assign variables

first coordinate : (x1,y1) = (-4,-2) so x1 = -4 and y1 = -2

second coordinate : (x2,y2) = (-2,-10) so x2 = -2 and y2 = -10

Next we plug in these values into the formula

Recall formula : [tex](\frac{x_1+x_2}{2} ,\frac{y_1+y_2}{2} )[/tex]

x1 = -4 , x2 = -2 , y1 - 2 and y2 = - 10

plug in values

[tex](\frac{-4+(-2))}{2} ,\frac{-2+(-10)}{2} )[/tex]

simplify numerators : -4 + -2 = -6 and -2 + -10 = -12

[tex](\frac{-6}{2} ,\frac{-12}{2} )[/tex]

simplify fractions : -6/2 = -3 and -12/2 = -6

the midpoint is (-3,-6)