Get expert insights and reliable answers to your questions on IDNLearn.com. Our experts provide timely and accurate responses to help you navigate any topic or issue with confidence.

A 1450 kg torpedo strikes a 780 kg target that is initially at rest. If the combined torpedo and target move forward with a speed of 8.65 m/s, what is the initial velocity of the torpedo? Assume that no resistance is provided by the water

Sagot :

If the torpedo's initial speed is v, then by conservation of momentum,

(1450 kg) v + 0 = (1450 kg + 780 kg) (8.65 m/s)

Solve for v :

(1450 kg) v = 19,116.5 kg•m/s

v ≈ 13.2 m/s