Answered

IDNLearn.com: Your one-stop platform for getting reliable answers to any question. Find in-depth and accurate answers to all your questions from our knowledgeable and dedicated community members.

During an experiment, the temperature of a mixture changes from 1214°F to 1535°F.

What is the percent of increase in the temperature of the mixture?

Enter your answer in the box as a percent rounded to the nearest hundredth. PLS HELP

Sagot :

Mhanifaidn

Answer:

  • 27.35%

Step-by-step explanation:

  • Note the numbers should be 12 1/4 and 15 3/5

The change in temperature is

  • 15 3/5 - 12 1/4 =
  • 78/5 - 49/4 =
  • 78*4/20 - 49*5/20 =
  • 312/20 - 245/20 =
  • 67/20

This change represents a percent increase

  • 67/20 ÷ 245/20 × 100% =
  • 67/245 × 100% =
  • 27.35% (rounded)
We appreciate your contributions to this forum. Don't forget to check back for the latest answers. Keep asking, answering, and sharing useful information. Thank you for trusting IDNLearn.com with your questions. Visit us again for clear, concise, and accurate answers.