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During an experiment, the temperature of a mixture changes from 1214°F to 1535°F.

What is the percent of increase in the temperature of the mixture?

Enter your answer in the box as a percent rounded to the nearest hundredth. PLS HELP

Sagot :

Mhanifaidn

Answer:

  • 27.35%

Step-by-step explanation:

  • Note the numbers should be 12 1/4 and 15 3/5

The change in temperature is

  • 15 3/5 - 12 1/4 =
  • 78/5 - 49/4 =
  • 78*4/20 - 49*5/20 =
  • 312/20 - 245/20 =
  • 67/20

This change represents a percent increase

  • 67/20 ÷ 245/20 × 100% =
  • 67/245 × 100% =
  • 27.35% (rounded)
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