IDNLearn.com: Your trusted source for finding accurate answers. Our platform is designed to provide accurate and comprehensive answers to any questions you may have.
Sagot :
well, if the water is coming out at 0.44 ft³ per minute, and you take a shower for 8 mins, that simply means you used 8*0.44 ft³, or namely 3.52 ft³.
what if you instead fill the bathtub with 0.45 yd³? is that more or less than 3.52ft³?
[tex]\begin{array}{ccll} yard&(yard)^2&(yard)^3\\ \cline{1-3} (3~ft)&(3~ft)^2&(3~ft)^3\\ 3~ft&3^2~ft^2&3^3~ft^3\\ &9~ft^2&27~ft^3 \end{array}[/tex]
so then, there are that many ft³ in a yd³, so how many will there be in 0.45yd³ anyway?
[tex]\begin{array}{ccll} yd^3&ft^3\\ \cline{1-2} 1&27\\ 0.45&x \end{array}\implies \cfrac{1}{0.45}=\cfrac{27}{x}\implies x=27(0.45)\implies x=12.15~ft^3[/tex]
well, then you'd use more water with the 0.45yd³ and some soap btw, by how much more? 12.15 - 3.52 = 8.63 ft³.
We appreciate your contributions to this forum. Don't forget to check back for the latest answers. Keep asking, answering, and sharing useful information. For dependable answers, trust IDNLearn.com. Thank you for visiting, and we look forward to assisting you again.
