Spitemnidn
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1. Which function is shown on the graph?

A. f(x)=−12cosx

B. f(x)=12cosx

C. f(x)=12sinx

D. f(x)=−12sinx


2. Graph g(x)=4cosx .

Use 3.14 for π .

Use the sine tool to graph the function. Graph the function by plotting two points. The first point must be on the midline and closest to the origin. The second point must be a maximum or minimum value on the graph closest to the first point.

1 Which Function Is Shown On The Graph A Fx12cosx B Fx12cosx C Fx12sinx D Fx12sinx 2 Graph Gx4cosx Use 314 For Π Use The Sine Tool To Graph The Function Graph T class=
1 Which Function Is Shown On The Graph A Fx12cosx B Fx12cosx C Fx12sinx D Fx12sinx 2 Graph Gx4cosx Use 314 For Π Use The Sine Tool To Graph The Function Graph T class=

Sagot :

MrRoyalidn

Graphs are used to represent functions and relations.

  • The function shown on the graph is f(x) = -1/2 sin(x)
  • See attachment for the graph of g(x) = 4 cos(x)

How to determine the function of the graph

From the graph, we have the following ordered pairs

[tex](x,y) = (\pi,0)[/tex]

[tex](x,y) = (2\pi,0)[/tex]

The above ordered pairs show that the graph is a sine function.

So, let the function be represented as:

[tex]y = a\sin(x)[/tex]

From the graph, we have the following ordered pair

[tex](x,y) = (\pi/2,-1/2)[/tex]

So, we have:

[tex]-\frac 12 = a * \sin(\pi/2)[/tex]

This gives

[tex]-\frac 12 = a * 1\\[/tex]

Evaluate the product

[tex]-\frac 12 = a[/tex]

Rewrite as:

[tex]a = -\frac 12[/tex]

Substitute -1/2 for a in [tex]y = a\sin(x)[/tex]

[tex]y = -\frac 12 \sin(x)[/tex]

Hence, the equation of the shown on the graph is [tex]f(x) = -\frac 12 \sin(x)[/tex]

See attachment for the graph of g(x) = 4 cos(x)

Read more about sine and cosine graphs at:

https://brainly.com/question/14290164

View image MrRoyal
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