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Sagot :
[tex]\qquad[/tex] ☀️[tex]\pink{\bf{ {Answer = \: \: 85.57g }}} [/tex]
Molar mass of [tex]\bf Cu_2O [/tex]
[tex]\qquad[/tex] [tex]\twoheadrightarrow\sf 63.546 \times 2 +16[/tex]
[tex]\qquad[/tex] [tex]\pink{\twoheadrightarrow\bf 143.092 g}[/tex]
As we know–
1 mol =[tex] \bf 6.02×10^{23} [/tex] formula units
1 mol[tex]\bf Cu_2O [/tex] = 143.092 g = [tex] \bf 6.02×10^{23} [/tex]formula units
Henceforth –
[tex]\bf 3.60×10^{23} [/tex] formula units [tex]\bf Cu_2O [/tex]–
[tex]\qquad[/tex] [tex]\sf :\implies \dfrac{143.092 \times3.60×10^{23 }}{6.02×10^{23}}[/tex]
[tex]\qquad[/tex] [tex]\sf :\implies \dfrac{143.092 \times3.60×\cancel{10^{23 }}}{6.02×\cancel{10^{23}}}[/tex]
[tex]\qquad[/tex] [tex]\pink{:\implies\bf 85.57 g}[/tex]
The number of grams in 3.60 x 10^23 formula units of CU2O would be 85.54 grams
Avogadro's constant
1 mole of any substance contains 6.022 x 10^23 atoms
In this case, the number of moles in 3.60 x 10^23 units of CU2O would be:
3.60 x 10^23/6.022 x 10^23 = 0.6 mole
Mass of 0.6 mole CU2O = 0.6 x 143.09
= 85.54 grams
More on Avogadro's constant can be found here: https://brainly.com/question/17818186
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