[tex]\qquad[/tex] ☀️[tex]\pink{\bf{ {Answer = \: \: 85.57g }}} [/tex]
Molar mass of [tex]\bf Cu_2O [/tex]
[tex]\qquad[/tex] [tex]\twoheadrightarrow\sf 63.546 \times 2 +16[/tex]
[tex]\qquad[/tex] [tex]\pink{\twoheadrightarrow\bf 143.092 g}[/tex]
As we know–
1 mol =[tex] \bf 6.02×10^{23} [/tex] formula units
1 mol[tex]\bf Cu_2O [/tex] = 143.092 g = [tex] \bf 6.02×10^{23} [/tex]formula units
Henceforth –
[tex]\bf 3.60×10^{23} [/tex] formula units [tex]\bf Cu_2O [/tex]–
[tex]\qquad[/tex] [tex]\sf :\implies \dfrac{143.092 \times3.60×10^{23 }}{6.02×10^{23}}[/tex]
[tex]\qquad[/tex] [tex]\sf :\implies \dfrac{143.092 \times3.60×\cancel{10^{23 }}}{6.02×\cancel{10^{23}}}[/tex]
[tex]\qquad[/tex] [tex]\pink{:\implies\bf 85.57 g}[/tex]