Answered

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Suppose that the width of a certain rectangle is 1 inch more than one-fourth of its length. The perimeter of the rectangle is 52 inches. Find the length and width of the rectangle.

Sagot :

Answer:

Length = 20

Width = 6

Step-by-step explanation:

Let the length of the rectangle be l inch, so, its width

[tex]w= (\frac{1}{4}l+1)[/tex]

So the perimeter equals:

[tex]P= 2l+2w=2l+2(\frac{1}{4}l+1)=2l+\frac{1}{2}l+2=\frac{5}{2}l+2[/tex]

[tex]52= \frac{5}{2}l+2[/tex]

[tex]50 = \frac{5}{2}l[/tex]    [tex]100=5l[/tex]      [tex]20 = l[/tex]

Hence width:

[tex]w = (\frac{1}{4}l+1)[/tex]

[tex]w=5+1 = 6[/tex]

Length = 20

Width = 6

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