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When camping alone, Mr. Adams uses all of the water in the storage barrel I. 12 days. If mrs. Adams caps with him, they use all the water in 8 days. In how many days will mrs. Adams use the water if she camps alone?

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Answer:

24 days

Explanation:

for Mr.Adams

12 days ---> 1 barrel of water

1 days ---> 1/12 barrel of water

8 days ---> [(1/12)*8] = 8/12 barrel of water

For Mrs Adams in 8 days:

she uses: 1 - 8/12 = 4/12

If she camps alone:

she uses 4/12 in 8 days

to use full:

(4/12)*3  barrels in  (8*3) days

1 barrels in 24 days

She can therefore use 24 days if she camps alone.

Mrs. Adams will use the water for 24 days.

Data;

  • Mr. Adams = 12 days
  • Mr. Adam + Mrs. Adam = 8 days

Fractions

To solve this problem, we have to know the fraction or proportion of water mrs. adam will use.

let mr. adam be represented by and mrs adam be represented by y

[tex]1/x + 1/ y = 1/8\\x= 12\\1/12 + 1/y = 1/8\\1/y = 1/8 - 1/12\\1/y = 1/24\\y = 24[/tex]

From the calculations above, Mrs. Adams will use the water for 24 days.

https://brainly.com/question/16981404

Learn more about fractions and proportions here;

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