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h(x)=
⎩
⎪
⎪
⎪
⎪
⎪
⎪
⎪
⎪
⎨
⎪
⎪
⎪
⎪
⎪
⎪
⎪
⎪
⎧
​

x
3

x
24
​
−1
(x−1)(x+3)
​

,
,
,
​

x∈(−∞,0]
x∈(0,8]
x∈(8,∞)
​

h
(
−
3
)
=
h(−3)=h, left parenthesis, minus, 3, right parenthesis, equals


Hx X 3 X 24 1 X1x3 X0 X08 X8 H 3 H3h Left Parenthesis Minus 3 Right Parenthesis Equals class=

Sagot :

Fieryanswererftidn

Answer:

h(-3) = -27

Step-by-step explanation:

given that h(-3)

a)

for x³

(-3)³

-27

b)

for [tex]\frac{24}{x}[/tex]-1

     [tex]\frac{24}{-3}[/tex]-1

    -8-1

     -9

c)

for (x-1)(x+3)

    (-3-1)(-3+3)

      0

Mirsalikhovhidn

Answer:

-27

Step-by-step explanation:

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