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Ignore the writing but someone help please

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Sagot :

Part (a)

The picture alone, without the frame, is 16 by 20

When accounting for the frame, the larger rectangle is 16+2x by 20+2x

We add up all four sides to get the perimeter

(16+2x)+(20+2x)+(16+2x)+(20+2x)

8x+72

or you can use this perimeter of a rectangle formula

P = 2(L+W)

P = 2(20+2x+16+2x)

P = 2(4x+36)

P = 8x+72

Answer: 8x+72

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Part (b)

Multiply the length and width to find the area of the rectangle.

area = length*width

A = L*W

A = (20+2x)*(16+2x)

A = 20(16+2x) + 2x(16+2x)

A = 320+40x + 32x + 4x^2

A = 4x^2 + 72x + 320

Answer: 4x^2 + 72x + 320

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Part (c)

Plug x = 2 into the perimeter equation found in part (a)

P = 8x+72

P = 8*2+72

P = 16+72

P = 88

Now plug x = 2 into the area equation found in part (b)

A = 4x^2 + 72x + 320

A = 4(2)^2 + 72(2) + 320

A = 4(4) + 72(2) + 320

A = 16 + 144 + 320

A = 160+320

A = 480

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Answers:

Perimeter = 88 inches

Area = 480 square inches

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