Discover a wealth of knowledge and get your questions answered at IDNLearn.com. Join our knowledgeable community and access a wealth of reliable answers to your most pressing questions.
Sagot :
[tex]~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$900\\ r=rate\to 4.75\%\to \frac{4.75}{100}\dotfill &0.0475\\ n= \begin{array}{llll} \textit{times it compounds per year} \end{array}\dotfill &1\\ t=years\dotfill &9 \end{cases} \\\\\\ A=900\left(1+\frac{0.0475}{1}\right)^{1\cdot 9}\implies A=900(1.0475)^9\implies A\approx 1366.6[/tex]
Thank you for being part of this discussion. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Thanks for visiting IDNLearn.com. We’re dedicated to providing clear answers, so visit us again for more helpful information.