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1. Find the perimeter of a square whose diagonal √14

Sagot :

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Answer:

P = 4 sqrt(7)

Step-by-step explanation:

The diagonal is sqrt(14)

The triangle is 45 - 45 -90

The side lengths would then be the hypotenuse divided by sqrt(2)

sqrt(14)/sqrt(2) = sqrt(7)

The perimeter of a square is

P =4 s where s is the side length

P = 4 sqrt(7)

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