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Sagot :
The maximum height of the ball is 5.1 m.
The horizontal distance or range of the ball is 35.4 m.
Maximum height of the ball
The maximum height attained by a projectile is the total vertical height reached by the projectile during the upward motion.
The maximum height of the ball is calculated as follows;
[tex]h = \frac{v^2 sin^2 \theta }{2g} \\\\h = \frac{(20)^2 \times (sin30)^2}{9.81} \\\\h = 5.1 \ m[/tex]
Distance of the ball
The horizontal distance or range of the ball is calculated as follows;
[tex]R = \frac{v^2 sin2\theta }{g} \\\\R= \frac{(20)^2 \times sin( 2\times 30)}{9.8} \\\\R =35.4 \ m[/tex]
Learn more about maximum height of projectile here: https://brainly.com/question/5626141
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