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Compute
900-841+784+...+36-25+16-9+4-1


Sagot :

If I understand your sequence, then this is the "closed form" of the sequence:

 a_n = 63 - 4 n

Sum = (59, 55, 51, 47, 43, 39, 35, 31, 27, 23, 19, 15, 11, 7, 3) = 465

Sum of the series 900-841+784+...+36-25+16-9+4-1 = 465.

What is a series?

A series is a set of numbers following some specific pattern.

What is an Arithmetic Progression?

An Arithmetic Progression (known as A.P.), is a special series where every term is the sum of the previous term and a constant(d), with the first term also being a constant(a).

How do we solve the given question?

We are given a series:

900 - 841 + 784 - ......... + 36 - 25 + 16 - 9 + 4 -1.

Taking two numbers at a time in this series, we get:

59, 55, 51, 47, 43, 39, 35, 31, 27, 23, 19, 15, 11, 7,  3.

The above series is an Arithmetic Progression, with first term a=3, the constant difference(d) = 4, the last term(l) = 59, and the number of terms(n) = 15

To find its sum, we use the formula of the sum of an Arithmetic Progression for first n numbers,

Sₙ = {(a+l)*n}/2

∴ Sum of the series = {(3+59)*15}/2 = (62*15)/2 = 31*15 = 465.

∴ Sum of the series 900-841+784+...+36-25+16-9+4-1 = 465.

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