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The molarity of the final solution is : 0.953 M
Given data :
mass of sucrose = 136.92 g
volume of solvent= 400ml
Total volume of solution = 420 ml
Moles of sucrose = mass / molar mass
= 136.92 / 342.31
= 0.40 mol
molarity of final solution = 0.40 / 0.420 = 0.953 M.
Hence we can conclude that The molarity of the final solution is : 0.953 M
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