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Sagot :
The resultant of the given forces is; 6√2 N
How to find the resultant of forces
We are given the forces as;
10 N along the x-axis which is +10 N in the x-direction
6 N along the y-axis which is +6N in the y-direction
4 N along the negative x-axis which is -4N
Thus;
Resultant force in the x-direction is; 10 - 4 = 6N
Resultant force in the y-direction is; 6N
Thus;
Total resultant force = √(6² + 6²)
Total resultant force = 6√2 N
Read more about finding resultant of a force at; https://brainly.com/question/14626208
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