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Find the resultant force of the following forces :
1) 10 N along x-axis
2) 6 N along y-axis
3) 4 N along negative x-axis

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Sagot :

The resultant force is 6√2 Newtons.

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The resultant of the given forces is; 6√2 N

How to find the resultant of forces

We are given the forces as;

10 N along the x-axis which is +10 N in the x-direction

6 N along the y-axis which is +6N in the y-direction

4 N along the negative x-axis which is -4N

Thus;

Resultant force in the x-direction is; 10 - 4 = 6N

Resultant force in the y-direction is; 6N

Thus;

Total resultant force = √(6² + 6²)

Total resultant force = 6√2 N

Read more about finding resultant of a force at; https://brainly.com/question/14626208

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