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HELP ASAP!! QUADRATIC FUNCTIONS!!

what is the equation in standard form of these points?

HELP ASAP QUADRATIC FUNCTIONS What Is The Equation In Standard Form Of These Points class=

Sagot :

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y=-x²+5x


Step by step explanation This is how I got the answer to your question and I gave you the solution I hope this helps you out
Tqiuidn

Answer:

[tex]-x^2+5x[/tex]

Step-by-step explanation:

Let the quadratic be [tex]ax^2+bx+c[/tex]. Therefore, if you plug in the first point,

[tex]a(0)^2+b(0)+c=0\\c=0[/tex]

and if you plug in the 2 other points,

[tex]a-b=-6\\4a+2b=6[/tex]

Multiply the first equation by 2:

[tex]2a-2b=-12[/tex]

and add it up to the second equation:

[tex]6a=-6\\a=-1[/tex]

Lastly, plug in a for the first equation:

[tex]-1-b=-6\\b=5[/tex]

Therefore, the final quadratic is [tex]\boxed{-x^2+5x}[/tex]

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