Get insightful responses to your questions quickly and easily on IDNLearn.com. Join our Q&A platform to receive prompt and accurate responses from knowledgeable professionals in various fields.
Sagot :
- Width be x
- Length be 2x
ATQ
[tex]\\ \tt\hookrightarrow Perimeter=88[/tex]
[tex]\\ \tt\hookrightarrow 2(x+2x)=88[/tex]
[tex]\\ \tt\hookrightarrow 2(3x)=88[/tex]
[tex]\\ \tt\hookrightarrow 6x=88[/tex]
[tex]\\ \tt\hookrightarrow 3x=44[/tex]
[tex]\\ \tt\hookrightarrow x=44/3\approx 15[/tex]
- Width=15
- Length=2(15)=30
Answer:
- L = 88/3 units
- W = 44/3 units
Step-by-step explanation:
We know that:
- Perimeter of rectangle: 88
- L = 2w
Solution:
- 2(L) + 2(w) = 88 units
- => 2(2w) + 2(w) = 88 units
- => 4w + 2w = 88 units
- => 6w = 88 units
- => w = 88/6 units
- => L = 2w
- => L = 2(14 2/3)
- => L = 2(44/3)
- => L = 88/3 units
Hence, the dimensions of the rectangle is:
- L = 88/3 units
- W = 44/3 units
We value your presence here. Keep sharing knowledge and helping others find the answers they need. This community is the perfect place to learn together. IDNLearn.com is committed to providing the best answers. Thank you for visiting, and see you next time for more solutions.
