Connect with a community of experts and enthusiasts on IDNLearn.com. Our platform is designed to provide quick and accurate answers to any questions you may have.
The coordinate of zero electric field of the two charges is (9.4 cm, 34.6 cm).
The electric field strength of a charge is defined as force per unit charge.
[tex]E= \frac{kq}{r^2} \\\\E = \frac{kq_1}{(x -6)^2} - \frac{kq_2}{(12 -x)^2} =0\\\\[/tex]
At zero net electric field, the electric field of the two charges will be equal.
Let the point of zero electric field = x
[tex]\frac{9 \times 10^9 \times 8 \times 10^{-12}}{(x -6)^2} - \frac{9 \times 10^9 \times 5 \times 10^{-12} }{(12 -x)^2} =0\\\\\frac{0.072}{x^2-12x + 36} - \frac{0.045}{144 -24x + x^2} =0\\\\0.045(x^2 -12x + 36) = 0.072(144-24x + x^2)\\\\0.045x^2 - 0.54x + 1.62= 10.368 - 1.728x + 0.072x^2\\\\0.027x^2 -1.188x + 8.748 = 0\\\\x = 9.4 \ cm, \ or \ 34.6\ cm[/tex]
Thus, the coordinate of zero electric field of the two charges is (9.4 cm, 34.6 cm).
Learn more about electric filed here: https://brainly.com/question/14372859