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SOMEONE PLS HELP WHAT DO I DO HERE

SOMEONE PLS HELP WHAT DO I DO HERE class=

Sagot :

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Answer:

see below

Step-by-step explanation:

4 ^(3x-1)=3

Take the natural log of each side

ln(4 ^(3x-1))= ln (3)

We know that ln ( a^b) = b ln a

(3x-1) ln 4 = ln 3

Divide each side by ln 4

3x-1 = ln(3)/ (ln4)

Add 1 to each side

3x = ln(3)/ ln (4) +1

Divide by 3

x =1/3 [( ln 3)/ ln (4)] + 1/3

x = .792461

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