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The equation of line c is y=
–
6x–3. Line d includes the point (3,
–
3) and is perpendicular to line c. What is the equation of line d?
Write the equation in slope-intercept form. Write the numbers in the equation as simplified proper fractions, improper fractions, or integers.

Sagot :

Adioabiolaidn

The equation of the line d as described is; y = x/6 + 7/2

Equation of a line

Since line d is perpendicular to line c;

Hence, the slope of line d is given as;

  • Slope(d) = -1/Slope(c)

And by comparison with the slope-intercept form of a linear equation, the Slope(c) = -6

  • Slope(d) = -1/-6

  • Slope (d) = 1/6.

Therefore, the equation of the line d which passes through the point, (3, -3) is;

  • 1/6 =( y-(-3))/(x-3)

By cross product;

  • 6y +18 = x-3

  • 6y = x-21

  • y = x/6 + 7/2

Read more on slope-intercept linear equations;

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