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Find the missing side length for each set of similar figures.

Find The Missing Side Length For Each Set Of Similar Figures class=

Sagot :

Fieryanswererftidn

Answer:

  • given below

Step-by-step explanation:

try to create equation to solve similarities maths:

[tex]\frac{side 1}{side 2} =\frac{side. 1 ..englarged}{side.2 ..enlarged}[/tex]

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question (a) answer:

[tex]\frac{x}{12.8} =\frac{20}{16}[/tex]

[tex]x=16[/tex]

............

[tex]\frac{y}{12.8} =\frac{10}{16}[/tex]

[tex]y=8[/tex]

..........................................

question (b) answer:

[tex]\frac{x}{22.5} =\frac{12}{9}[/tex]

[tex]x=30[/tex]

..........

[tex]\frac{y}{9} =\frac{35}{22.5}[/tex]

[tex]y=14[/tex]

Mavivianidn

3. you would do [tex]\frac{x}{20} = \frac{12.8}{16}[/tex] they are similar triangles, meaning that their sides are proportional. Based on the photo, it is assumable that x and 20 are proportional, so we can write is as a fraction. Then you can take 12.8 and 16 which are also proportional and say it is equal to [tex]\frac{x}{20}[/tex] because corresponding sides yay math woohoo! anyway, you can solve that equation by doing cross products:

[tex]16x = 12.8 * 20\\16x = 256\\x = 16[/tex]

You would then do the same steps for y:

[tex]\frac{y}{10}=\frac{16}{20}[/tex] you could also do [tex]\frac{y}{10} = \frac{12.8}{16}[/tex], but you may notice that 10 fits into 20 two times so you do not even need to do cross products. y = 8.

Follow these steps for #5! good luck have fun nice day

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