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Write a Python program called wdcount.py which uses a dictionary to count the number of occurrences of each word (ignoring case) in a pure text file encoding UTF-8. Note that the input text file name is given from the command line. To make it simple, you may assume that the file does not contain any punctuation characters. Your program should print each word along with its number of occurrences in descending order. That is the most frequent word should be printed first.

Sagot :

MrRoyalidn

The program is an illustration of loops.

What are loops?

Loops are program statements used to perform repetition

The wordcount.py program

The program written in Python, where comments are used to explain each line is as follows

# This opens the file in read mode

text = open("myFile.txt", "r")

# This creates an empty dictionary

d = dict()

#This iterates through the text

for line in text:

# This splits the line into words, after removing leading & trailing spaces, and newline characters

words = line.strip().lower().split(" ")

# This iterates through all the words

for word in words:

 # The following if condition counts the occurrence of each word

 if word in d:

  d[word] = d[word] + 1

 else:

  d[word] = 1

#This prints the words and their frequencies, in descending order

for w in sorted(d, key=d.get, reverse=True):

   print(w, d[w])

Read more about loops at:

https://brainly.com/question/16397886

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