Answered

IDNLearn.com is your trusted platform for finding reliable answers. Join our Q&A platform to get accurate and thorough answers to all your pressing questions.

The H⁺ concentration in an aqueous solution at 25 °C is 9.1 × 10⁻⁴. What is [OH⁻]?

Sagot :

Steps:-

  • First we calculate pH then pOH then [OH-]

[tex]\\ \tt\rightarrowtail pH=-log[H^+][/tex]

[tex]\\ \tt\rightarrowtail pH=-log[9.1\times 10^{-4}][/tex]

[tex]\\ \tt\rightarrowtail pH=-log9.1-log10^{-4})[/tex]

[tex]\\ \tt\rightarrowtail pH=0.95+4[/tex]

[tex]\\ \tt\rightarrowtail pH=4.95[/tex]

Now

[tex]\\ \tt\rightarrowtail pH+pOH=14[/tex]

[tex]\\ \tt\rightarrowtail pOH=14-4.95[/tex]

[tex]\\ \tt\rightarrowtail pOH=9.05[/tex]

So

[tex]\\ \tt\rightarrowtail -log[OH^-]=9.05[/tex]

[tex]\\ \tt\rightarrowtail log[OH^-]=-9.05[/tex]

[tex]\\ \tt\rightarrowtail OH^-=10^{-9.05}[/tex]

[tex]\\ \tt\rightarrowtail OH^-=8.91\times 10^{-4}[/tex]

Your participation means a lot to us. Keep sharing information and solutions. This community grows thanks to the amazing contributions from members like you. Your search for answers ends at IDNLearn.com. Thanks for visiting, and we look forward to helping you again soon.