Discover a wealth of knowledge and get your questions answered on IDNLearn.com. Discover in-depth and trustworthy answers to all your questions from our experienced community members.
Sagot :
The initial temperature of the solution before the reaction occurred is; 24°C
Stoichiometry Calculations
The reaction between the hydrogen ion and hydroxide ion will be;
H⁺ + OH⁻ → H₂O
We can see that the ratio of hydrogen ions to hydroxide ions is 1:1.
Thus,
No. of moles of H⁺ = volume × concentration of H⁺
We are given;
Volume of H⁺ = 150 mL = 0.15 L
Concentration of H⁺ = 0.4 M
Thus;
No. of moles of H⁺ = 0.15 * 0.4
No. of moles of H⁺ = 0.06 mol
In a similar fashion;
No. of moles of OH⁻ = volume × concentration of OH⁻
We are given;
Volume of OH⁻ = 200 mL = 0.2 L
Concentration of OH⁻ = 0.5 M
Thus;
No. of moles of OH⁻ = 0.2 * 0.5
No. of moles of OH⁻ = 0.1 mol
Thus, the ratio of number of moles of hydrogen ions to number of moles of hydroxide ions is 0.06:0.1
Now, hydroxide ions (OH⁻) are present in excess and as such hydrogen ions (H⁺) will be the limiting reagent.
Thus;
No. of moles of water formed = No. of moles of ions = 0.06 mol.
Thus;
heat released = moles of H⁺ ions * enthalpy of neutralization(ΔH_neutr)
heat released = 0.06 mol * -62 kj/mol
heat released = 3.72 kJ = 3720 J
From energy balance, we know that;
Amount of heat released = Amount of heat absorbed by the solution
Thus;
3720 = m*c*ΔT
3720 = 350 * 4.184 * (26.5 - T)
where T is the initial temperature.
Solving for T gives T = 24°C
Read more about Stoichiometry at; https://brainly.com/question/16060223
We appreciate your presence here. Keep sharing knowledge and helping others find the answers they need. This community is the perfect place to learn together. IDNLearn.com provides the answers you need. Thank you for visiting, and see you next time for more valuable insights.
