Ekiyarraidn
Answered

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5​(x−3​)−6x≥−3

Please don’t take it down just solve for x

Sagot :

Given :

[tex]5(x−3)−6x≥−3[/tex]

Now opening brackets,

[tex]5x - 15 - 6x \geqslant - 3[/tex]

[tex] = > (5 - 6)x - 15 \geqslant - 3[/tex]

[tex] = > - x - 15 \geqslant - 3[/tex]

[tex] = > - x \geqslant - 3 + 15[/tex]

[tex] = > - x \geqslant (15 - 3)[/tex]

[tex] = > - x \geqslant 12[/tex]

[tex] = > x \leqslant - 12[/tex]

Hence the answer is [tex] x \leqslant - 12[/tex]

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