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Solve log x = 2.

100

1,000

2

20


Sagot :

keeping in mind that when the logarithm base is omitted, the base 10 is assumed.

[tex]\textit{exponential form of a logarithm} \\\\ \log_a(b)=y \qquad \implies \qquad a^y= b \\\\[-0.35em] ~\dotfill\\\\ \log(x)=2\implies \log_{10}(x)=2\implies 10^2=x\implies 100=x[/tex]