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find the 37th term of the arithmetic sequence 412,404,396

Sagot :

S1m1idn

Answer:

124

Step-by-step explanation:

Is an arithmetic sequence so we know we need to add or subtract something

we see the numbers get lower we need to subtract something

a1=412,  a2 = 412-8= 404, a3 =404-8 = 396

so the common difference d = (-8)

nth term = first term + position of the term· common difference

         an =        a1     +              (n-1)              ·         d

       a37 =       412    +            (37-1)             ·         (-8)

a37 = 412+ 36(-8)

a37 = 412 -288

a37 = 124

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