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Directions: Solve the following equations by using the rules for removing the parentheses.

1. 4(x - 3) = 32

2. 12(2x + 4) = 24

3. 3(3s + 4) = 21

4. 3(c - 2) = 2(c + 3)

5. 12(r - 3) = 6(r + 3)

6. 2(x+5) = 30

7. 3(b+2) = 6(b-2)

8. 4(c-2) = 16

9. 7(y+2) = 28

10. 4(d-2) = 2(d+3)

11. 5(L+5) = 35

12. 2(k-2) = 44

13. p-7 = 11

14. 3(s+3) = 27

15. 5(a-3) = 45

Sagot :

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Answer:

1. x = 11

2. x = -1

3. s = 1

4. c = 12

5. r = 9

6. x = 10

7. b = 6

8. c = 6

9. y = 2

10. d = 7

11. L = 2

12. k = 24

13. p = 18

14. s = 6

15. a = 12

Obinnachetachukwuidn

Answer:

1. 4(x -3) = 32

4x - 12 = 32

4x = 32 - 12

4x = 20

4x /4 = 20 /4

x = 5

2 . 12 ( 2x + 4 ) = 24

24x + 48 = 24

24x = 24 - 48

24x = - 24

Divide both sides by 24

x = - 1

3. 3 ( 3s + 4) = 24

9s + 12 = 24

9s = 24 - 12

9s = 12

9s = 12

Divide both sides by 9

s = 12 /9

4. 3 ( c - 2 ) = 2 ( c +3 )

3c - 6 = 2c + 6

3c - 2c = 6 + 6

c = 12

5 . 12(r - 3 )= 6 (r + 3)

12r - 36 = 6r + 18

12r - 6r = 18 + 36

6r = 54

Divide both sides by 6

r = 9

6 . 2 ( x + 5 ) = 30

2x + 10 = 30

2x = 30 - 10

2x = 20

x = 10

Too long to type steps already explained

BUT I HELPED ☆☆

Plssss Mark brainlest

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