Find expert answers and community insights on IDNLearn.com. Our platform offers comprehensive and accurate responses to help you make informed decisions on any topic.
This question involves the concepts of electric field strength and distance.
The strength of the electric field is "215760 N/C".
The electric field strength due to a charge is given by the following formula:
[tex]E = \frac{kq}{r^2}[/tex]
where,
Therefore,
[tex]E=\frac{(8.99\ x\ 10^9\ N.m^2/C^2)(6\ x\ 10^{-6}\ C)}{(0.5\ m)^2}[/tex]
E = 215760 N/C
Learn more about electric field strength here:
https://brainly.com/question/4264413
This question involves the concepts of electric field strength and distance.The strength of the electric field is "215760 N/C".
The electric field strength due to a charge is given by the following formula:
[tex]E=\dfrac{kq}{r^2}[/tex]
where,
E = Electric Field Strength = ?
k = Colomb's constant = 8.99 x 10⁹ N.m²/C²
q = magnitude of charge = 6 μC = 6 x 10⁻⁶ C
r = distance = 0.5 m
Therefore, putting the values in the formula;
[tex]E=\dfrac{(8.99\times 10^9)(6\times 10^{-6})}{0.5}[/tex]
E = 215760 N/C
Thus the strength of the electric field is "215760 N/C".
Learn more about electric field strength here:
brainly.com/question/4264413