Find answers to your questions faster and easier with IDNLearn.com. Ask any question and receive accurate, in-depth responses from our dedicated team of experts.
Sagot :
A) The work done by the shaft is; W_s = 1.08721 kJ
B) The work done in displacing the atmosphere is; W_atm = 1.4337 kJ
C) The heat transfer to the gas is; Q = 2.821 kJ
D) The detailed account of the heat transfer of energy to the gas is; done using concept of first law of thermodynamics
Understanding First Law of Thermodynamics
From the attached image, we see the vertical piston-cylinder assembly and we are given the values;
Mass of piston and shaft; m = 25 kg
Change in potential energy; ΔPE = 0.2 kJ = 200 J
Force Exerted; F_s = 1334 N
Diameter of Piston; D = 15 cm
Area of Shaft; A_shaft = 0.8 cm²
Atmospheric Pressure; P_atm = 1 bar = 100000 Pa
Change in internal energy of gas; ΔU_gas = 0.1 kJ = 100 J
A) Let us first find the change in height from;
ΔPE = mg*Δz
Δz = ΔPE/(mg)
Δz = 200/(25 * 9.81)
Δz = 0.815 m
Work done by shaft is gotten from the formula;
W_s = F_s * Δz
W_s = 1334 * 0.815
W_s = 1087.21 J
W_s = 1.08721 kJ
B) The net area is gotten from;
A_net = A_piston - A_shaft
A_net = ((π * 15²)/4) - 0.8
A_net = 175.915 cm² = 0.0175915 m²
Work done against the atmosphere is;
W_atm = P_atm * A_net * Δz
W_atm = 100000 * 0.0175915 * 0.815
W_atm = 1433.7 J
W_atm = 1.4337 kJ
C) Total work done by the system is gotten from;
W = W_s + W_atm
W = 1087.21 + 1433.7
W = 2,520.91 J
W = 2.521 kJ
From first law of thermodynamics we can arrive at;
Q = ΔU_gas + ΔPE_piston and shaft + W
Plugging in the relevant values gives;
Q = 100 + 200 + 2,520.91
Q = 2820.91 J
Q = 2.821 kJ
Read more about first law of thermodynamics at; https://brainly.com/question/15071682

We appreciate every question and answer you provide. Keep engaging and finding the best solutions. This community is the perfect place to learn and grow together. IDNLearn.com is committed to your satisfaction. Thank you for visiting, and see you next time for more helpful answers.