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What is an equation of the line that passes through the points (-6,-5) and
(-2, 3)

Sagot :

Nonportritidn

Answer:

[tex]y=-0.500x+2[/tex]

Step-by-step explanation:

Given the following question:

point A = (-6, 5)
point B = (-2, 3)

To find the equation of the line we have to find the slope intercept, where m is the slope of the given line.

Formula for slope intercept:

[tex]y=mx+b[/tex]

First, we need to fine the slope of the given points because m is the slope.

[tex]m=\frac{y2-y1}{x2-x1}[/tex]
[tex]m=\frac{3-5}{2--6} =\frac{-2}{4} =-0.500[/tex]
[tex]m=-0.500[/tex]

[tex]y=mx+b[/tex]
[tex]y=5[/tex]
[tex]m=-0.500[/tex]
[tex]x=-6[/tex]
[tex]5=-0.500(-6)+b[/tex]
[tex]-0.500\times-6=3[/tex]
[tex]5=3+b[/tex]
[tex]5-3=2[/tex]
[tex]2+b[/tex]
[tex]b=2[/tex]

[tex]y=-0.500x+2[/tex]

Hope this helps.

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