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Two parents have the following genotypes at 4 genes - AaBbCcDd x aaBbccDd. What is the probability of them having one offspring that displays either the dominant trait for all 4 genes or the recessive trait for all 4 genes (Give your answer to 5 decimal places).

Sagot :

Answer:

a b c d e f g h i dont know and im very sory

Explanation:

The probability of having one offspring that displays either the dominant trait for all 4 genes or the recessive trait for all 4 genes by the parents that have the following genotypes at 4 genes - AaBbCcDd x aaBbccDd is 0.51563.

What do you mean by dominant trait?

  • The characters/ trait which can be expressed in offspring.

What do you mean by recessive trait?

  • The character/trait which is present but do not express in offspring.

What are genes?

  • These are the hereditary units that carries information from one generation to next.

What is genotypes?

  • "It is the genetic make up of an organisms."

The probability of occurrence of more or more genes can be determined using punnette square. "The Punnett square is a square diagram that is used to predict the genotypes of a particular cross or breeding experiment."

The calculation of probability of expressed traits is shown in the diagram given below.

Hence, the answer is 0.51563.

To know more about Punnette square here

https://brainly.com/question/25357981

#SPJ2

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