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Sagot :
Answer:
mABC = 81°
mCAB = 59°
Let’s start with finding mCAB.
Segment CD is a straight line that runs through A, so we know it is a total of 180°.
The problem tells us that there is a right angle (90°) and gives us that 31° in between. Since they all have to add up to 180, we can do
180 - 90 - 31 = ...59°!
Now that we have mCAB, we can find mABC.
All the angles in any triangle must add up to 180. Since we now know mCAB (59°) and mCBA (40°), we can subtract to find the missing angle.
180 - 59 - 40 = ...81°!
Hope this helps! Brainliest always appreciated
mABC = 81°
mCAB = 59°
Let’s start with finding mCAB.
Segment CD is a straight line that runs through A, so we know it is a total of 180°.
The problem tells us that there is a right angle (90°) and gives us that 31° in between. Since they all have to add up to 180, we can do
180 - 90 - 31 = ...59°!
Now that we have mCAB, we can find mABC.
All the angles in any triangle must add up to 180. Since we now know mCAB (59°) and mCBA (40°), we can subtract to find the missing angle.
180 - 59 - 40 = ...81°!
Hope this helps! Brainliest always appreciated
[tex]m[/tex]∠ABC
∠A, first off we can use vertical angles to figure out that angle A is [tex]90-31[/tex] which is 59° and since we know C is 40° we can make an equation
[tex]59+40+x=180[/tex] which we get that angle B equals 81° which makes [tex]m[/tex]∠ABC Acute
[tex]m[/tex]∠CAB
this is an acute triangle because it is the exact same as [tex]m[/tex]∠ABC, but just expressed differently.
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