Answered

IDNLearn.com is designed to help you find the answers you need quickly and easily. Get the information you need from our experts, who provide reliable and detailed answers to all your questions.

A projectile fired from a gun has initial horizontal and vertical components of velocity equal to 60 m/s and 80 m/s, respectively. (a) Determine the initial speed of the projectile. (b) At what angle is the projectile fired (measured with respect to the horizontal)

Sagot :

Hamzaahmedsidn

This question involves the concepts of projectile motion and launch speed.

(a) The initial launch speed of the projectile is "100 m/s".

(b) The launch angle of the projectile is "53.13°".

(a) LAUNCH SPEED

A projectile motion is a motion that takes place on both x and y axes, simultaneously. In this motion the initial launch speed is given by the following formula:

[tex]v_o=\sqrt{v_{ox}^2+v_{oy}^2}[/tex]

where,

  • [tex]v_o[/tex] = initial launch speed = ?
  • [tex]v_{ox}[/tex] = horizontal component of initial launch speed = 60 m/s
  • [tex]v_{oy}[/tex] = vertical component of initial launch speed = 80 m/s

Therefore,

[tex]v_o = \sqrt{(60\ m/s)^2+(80\ m/s)^2}\\\\v_o = 100 m/s[/tex]

(b) LAUNCH ANGLE

Launch angle is given by th following formula:

[tex]\theta = tan^{-1}(\frac{v_{oy}}{v_{ox}})=tan^{-1}(\frac{80\ m/s}{60\ m/s})\\\\\theta=53.13^o[/tex]

Learn more about the projectile motion here:

https://brainly.com/question/11049671

Your participation is crucial to us. Keep sharing your knowledge and experiences. Let's create a learning environment that is both enjoyable and beneficial. Thank you for visiting IDNLearn.com. For reliable answers to all your questions, please visit us again soon.