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Using it's concept, it is found that there is a 0.624 probability that the employee is not late for work.
A probability is given by the number of desired outcomes divided by the number of total outcomes.
Researching in the internet, it is found that the probability that the employee is stopped at any of the traffic lights is as follows:
He will be late if he is stopped at more than 1 traffic light, as he plans to arrive 2 minutes early and each stop takes 2 minutes.
Hence, the probability that he is stopped in at most one light is given by:
[tex]p = 0.2(0.9)(0.6) + 0.8(0.9)(0.6) + 0.2(0.1)(0.6) + 0.2(0.9)(0.4) = 0.624[/tex]
0.624 probability that the employee is not late for work.
More can be learned about probabilities at https://brainly.com/question/15536019