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A 27.76 N crate is being lowered down at a constant rate along an inclined ramp by a massless rope. Find the magnitude of force F in N if the angle between the ramp and the horizontal is 30 degrees and coefficient of kinetic friction is 0.2. See the figure attached.

My attempt at solution:

Sum F y = 0
F y = F n - F g y
F n = m g cos(30)

Sum F x = F g x - F - f k = 0
F = F g x - f k
F = m g sin(30) - mu k Fn
F = m g sin(30) - 0.2(m g cos(30))

F = 27.76sin(30) - 0.2(27.76cos(30))
F = 9 N

A 2776 N Crate Is Being Lowered Down At A Constant Rate Along An Inclined Ramp By A Massless Rope Find The Magnitude Of Force F In N If The Angle Between The Ra class=

Sagot :

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The magnitude of the force F is 4.8 N.

What is frictional force?

The frictional force is the force that tends to oppose the relative motion between two surfaces in contact.

We must recall that;

μ= F/R

When R = W cos θ

So;

μ= F/W cos θ

μ= coefficient of friction

F = force acting on the crate

W = weight of the crate

0.2 = F/27.76 cos 30

F = 0.2 × 27.76 cos 30

F = 4.8 N

Learn more about frictional force: https://brainly.com/question/1714663

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